document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149554>Question 149554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me write 3(cos 60 degrees + i sin 60 degrees) in the form of a + bi!<BR>\n" );
document.write( "Thank you, Tami </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122239 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me write 3(cos 60 degrees + i sin 60 degrees) in the form of a + bi!<BR>\n" );
document.write( "Thank you, Tami<BR>\n" );
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document.write( "3(cos 60 degrees + i sin 60 degrees)<BR>\n" );
document.write( "cos(60º) = 1/2<BR>\n" );
document.write( "sin(60º) = (1/2)sqrt(3)<BR>\n" );
document.write( "= 3[(1/2) + i*sqrt(3)/2]<BR>\n" );
document.write( "= 3/2 + i*(3*sqrt(3)/2)<BR>\n" );
document.write( "a = 3/2<BR>\n" );
document.write( "b = (3/2)*sqrt(3)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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