document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165848>Question 165848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a football field is 67 yards greater than the width.   the perimeter of the field is 346 yards. find the length and width of the football field. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122238 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=PERIMETER.<BR>\n" );
document.write( "W=L+67<BR>\n" );
document.write( "2L+2(L+67)=346<BR>\n" );
document.write( "2L+2L+134=346<BR>\n" );
document.write( "4L=346-134<BR>\n" );
document.write( "4L=212<BR>\n" );
document.write( "L=212/4<BR>\n" );
document.write( "L=53 YDS. IS THE LENGTH.<BR>\n" );
document.write( "W=53+67=120 YDS. FOR THE WIDTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*53+2*120=346<BR>\n" );
document.write( "106+240=346<BR>\n" );
document.write( "346=346 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );