document.write( "Question 165798: roger has $3.10 consisting of quarters, dimes and nickels. He has twice as man quarters as dimes and three more dimes than nickels. find the number of each coin. \n" ); document.write( "
Algebra.Com's Answer #122226 by Mathtut(3670)\"\" \"About 
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q = # of quarters d = # dimes and n = # of nickels\r
\n" ); document.write( "\n" ); document.write( ".25q+.1d+.05n=3.10
\n" ); document.write( "q=2d
\n" ); document.write( "n=d-3\r
\n" ); document.write( "\n" ); document.write( "substitute \".25%282d%29%2B.1d%2B.05%28d-3%29=3.1\"
\n" ); document.write( " \".5d%2B.1d%2B.05d-.15=3.1\" combining\".65d=3.25\" \"d=5\"
\n" ); document.write( "so \"q=2%285%29=10\" and \"n=5-3=2\"\r
\n" ); document.write( "\n" ); document.write( "q=10
\n" ); document.write( "d=5
\n" ); document.write( "n=2
\n" ); document.write( "
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