document.write( "Question 23417: Find the first five (5) terms of the sequence (begin with n = 1).
\n" ); document.write( "A=n!/n^2\r
\n" ); document.write( "\n" ); document.write( "I still do not understand how to do this one.
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Algebra.Com's Answer #12221 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
First, hopefully you know what n! means. \r
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\n" ); document.write( "\n" ); document.write( "For examples:
\n" ); document.write( " 1! = 1
\n" ); document.write( "2! = 2*1 = 2
\n" ); document.write( "3!= 3*2*1=6
\n" ); document.write( "4!=4*3*2*1 = 24
\n" ); document.write( "5! = 5*4*3*2*1 = 120\r
\n" ); document.write( "\n" ); document.write( "etc.\r
\n" ); document.write( "\n" ); document.write( "n! = the product of the integers beginning with n and counting down to 1.\r
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\n" ); document.write( "\n" ); document.write( "Now, \"A=+%28n%21%29%2F%28n%5E2%29+\"\r
\n" ); document.write( "\n" ); document.write( "Beginning with n=1:
\n" ); document.write( "n=1, so \"A+=+1%2F%281%5E2%29=+1\"
\n" ); document.write( "n=2, so \"A+=+%282%2A1%29%2F%282%5E2%29=+2%2F4=1%2F2\"
\n" ); document.write( "n=3, so \"A+=+%283%2A2%2A1%29%2F%283%5E2%29=+6%2F9=+2%2F3\"
\n" ); document.write( "n=4, so \"A+=+%284%2A3%2A2%2A1%29%2F%284%5E2%29=+24%2F16=3%2F2\"
\n" ); document.write( "n=5, so \"A+=+%285%2A4%2A3%2A2%2A1%29%2F%285%5E2%29=+120%2F25=+24%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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