document.write( "Question 165784: 4x^2>13x-3 \n" ); document.write( "
Algebra.Com's Answer #122206 by checkley77(12844)\"\" \"About 
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4x^2>13x-3
\n" ); document.write( "4x^2-13x>-3
\n" ); document.write( "x(4x-13)>0
\n" ); document.write( "x>0
\n" ); document.write( "4x-13>0
\n" ); document.write( "4x>13
\n" ); document.write( "x>13/4
\n" ); document.write( "let x=.1
\n" ); document.write( "let x=14/4=7/2
\n" ); document.write( "4*.1^2>13*.1-3
\n" ); document.write( "4*.01>13*.1-3
\n" ); document.write( ".04>1.3-3
\n" ); document.write( ".04>-1.7
\n" ); document.write( "and:
\n" ); document.write( "4*7/2^2>13*7/2-3
\n" ); document.write( "4*49/4>91/2-3
\n" ); document.write( "196/4>(91-3*2)/2
\n" ); document.write( "98/2>(91-6)/2
\n" ); document.write( "49>85/2
\n" ); document.write( "49>42.5
\n" ); document.write( " \n" ); document.write( "
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