document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165764>Question 165764</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0757521185/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> a carpet layer wishes to determine the cost of carpeting a rectangular room whose perimeter is 52 feet. Suppose that the length of the room is 4 feet more than its width. Find<BR>\n" );
document.write( "(a) the length and width of the room<BR>\n" );
document.write( "(b) the cost of the carpet if it costs $18.95 per square yard\r<BR>\n" );
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document.write( "Need help setting up this problem </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122194 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  so we are given P-perimeter as 52 feet we know that P=2(L+W) the length or L is 4 more fee than the width  L=W+4   so substitution our given and the L value in the 2nd equation into our perimeter formula we get 52=2((W+4)+W) lets distribute the right side 52=4W+8 so subtract 8 both sides and 4W=44 divide each side by 4 and W=11    L=W(11)+4 so L=15\r<BR>\n" );
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document.write( "a. width is 11 feet <BR>\n" );
document.write( "   length is 15 feet\r<BR>\n" );
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document.write( "b  A=15 times 11=165 sq ft but we must divide this by 9 to get square yards<BR>\n" );
document.write( "    so 165/9=18.33 sq yards<BR>\n" );
document.write( "   so 18.33 sq yd multiplied by cost per yard of $18.95 equals $347.35 as    being the cost of the carpet for this given room </SPAN>\n" );
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