document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165745>Question 165745</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321368541/algebrahomeworkh>Elementary and Intermdiate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The larger of two numbers is 5 less than twice the smaller number.  The sum of the two numbers is 28.  What are the numbers?\r<BR>\n" );
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document.write( "Known:  sum of the numbers = 28<BR>\n" );
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document.write( "I am stuck. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122181 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lets call the smaller a and the larger b\r<BR>\n" );
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document.write( "b=2a-5  a+b=28  solve for a in the 2nd equation and we get a=28-b.  now take the value of a and substitute it into the 1st equation.                         b=2(28-b)-5  now distribute the right side<BR>\n" );
document.write( "b=56-2b-5 combine terms<BR>\n" );
document.write( "b=51-2b  add 2b to each side<BR>\n" );
document.write( "3b=51 divide by 3<BR>\n" );
document.write( "b=17   and since a=28-b(17) then a =11\r<BR>\n" );
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document.write( "so the smaller number is 11 and the larger is 17<BR>\n" );
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