document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165692>Question 165692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train normally travels 60 miles at a certain speed. one day,due to bad weather, the train's speed is reduced by 10mph so that the journey takes 3 hours longer. find the normal speed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122172 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "60=RT<BR>\n" );
document.write( "R=60/T<BR>\n" );
document.write( "60=(R-10)(T+3)<BR>\n" );
document.write( "60=(60/T-10)(T+3)<BR>\n" );
document.write( "60=60T/T+180/T-10T-30<BR>\n" );
document.write( "60=60+180/T-10T-30<BR>\n" );
document.write( "60-60+30=180/T-10T<BR>\n" );
document.write( "30=(180-10T^2)/T<BR>\n" );
document.write( "30T=180-10T^2<BR>\n" );
document.write( "10T^2+30T-180=0<BR>\n" );
document.write( "10(T^2+3T-18)=0<BR>\n" );
document.write( "10(T+6)(T-3)<BR>\n" );
document.write( "T-3=0<BR>\n" );
document.write( "T=3<BR>\n" );
document.write( "R=60/3<BR>\n" );
document.write( "R=20 MPH <BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "60=(20-10)(3+3)<BR>\n" );
document.write( "60=10*6<BR>\n" );
document.write( "60=60\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );