document.write( "Question 165720: 6x^2-x-5 solve for x \n" ); document.write( "
Algebra.Com's Answer #122163 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I assume that the equation is really \"6x%5E2-x-5=0\"\r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"6%2Ax%5E2-x-5=0\" ( notice \"a=6\", \"b=-1\", and \"c=-5\")
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\n" ); document.write( " \"x+=+%28--1+%2B-+sqrt%28+%28-1%29%5E2-4%2A6%2A-5+%29%29%2F%282%2A6%29\" Plug in a=6, b=-1, and c=-5
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\n" ); document.write( " \"x+=+%281+%2B-+sqrt%28+%28-1%29%5E2-4%2A6%2A-5+%29%29%2F%282%2A6%29\" Negate -1 to get 1
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\n" ); document.write( " \"x+=+%281+%2B-+sqrt%28+1-4%2A6%2A-5+%29%29%2F%282%2A6%29\" Square -1 to get 1 (note: remember when you square -1, you must square the negative as well. This is because \"%28-1%29%5E2=-1%2A-1=1\".)
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\n" ); document.write( " \"x+=+%281+%2B-+sqrt%28+1%2B120+%29%29%2F%282%2A6%29\" Multiply \"-4%2A-5%2A6\" to get \"120\"
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\n" ); document.write( " \"x+=+%281+%2B-+sqrt%28+121+%29%29%2F%282%2A6%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%281+%2B-+11%29%2F%282%2A6%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%281+%2B-+11%29%2F12\" Multiply 2 and 6 to get 12
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"x+=+%281+%2B+11%29%2F12\" or \"x+=+%281+-+11%29%2F12\"
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\n" ); document.write( " Lets look at the first part:
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\n" ); document.write( " \"x=%281+%2B+11%29%2F12\"
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\n" ); document.write( " \"x=12%2F12\" Add the terms in the numerator
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\n" ); document.write( " \"x=1\" Divide
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\n" ); document.write( " So one answer is
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\n" ); document.write( " \"x=1\"
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\n" ); document.write( " Now lets look at the second part:
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\n" ); document.write( " \"x=%281+-+11%29%2F12\"
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\n" ); document.write( " \"x=-10%2F12\" Subtract the terms in the numerator
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\n" ); document.write( " \"x=-5%2F6\" Divide
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\n" ); document.write( " So another answer is
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\n" ); document.write( " \"x=-5%2F6\"
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\n" ); document.write( " So our solutions are:
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\n" ); document.write( " \"x=1\" or \"x=-5%2F6\"
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