document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165656>Question 165656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two brothers, Bob and Bill live 450 miles apart. Starting at the same time, they plan to drive until they meet. Bill averages 10 miles per hour faster than Bob who averages 50 mph. How long will it take for them to meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122145 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) equals Rate(r) times Time(t)or d=rt; r=d/t and t=d/r\r<BR>\n" );
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document.write( "Let t=time it takes 'till they meet\r<BR>\n" );
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document.write( "Distance Bob drives=50t<BR>\n" );
document.write( "Distance Bill drives =60t<BR>\n" );
document.write( "Now when the above two distances add up to 450 miles, they will have met, so:\r<BR>\n" );
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document.write( "50t+60t=450 collect like terms<BR>\n" );
document.write( "110t=450 divide each side by 110<BR>\n" );
document.write( "t=4.1 hr----------------------------time it takes them to meet\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "50*4.1+60*4.1=450<BR>\n" );
document.write( "204.5+245.5=450<BR>\n" );
document.write( "~~~450=450\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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