document.write( "Question 165662: the width of a rectangle is 3 feet less than its length. if the perimeter is 22 feet, what are both its length and width? \n" ); document.write( "
Algebra.Com's Answer #122137 by midwood_trail(310)\"\" \"About 
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The width of a rectangle is 3 feet less than its length. if the perimeter is 22 feet, what are both its length and width?\r
\n" ); document.write( "\n" ); document.write( "width = x - 3\r
\n" ); document.write( "\n" ); document.write( "length = x\r
\n" ); document.write( "\n" ); document.write( "perimeter = 22\r
\n" ); document.write( "\n" ); document.write( "P = 2L + 2W\r
\n" ); document.write( "\n" ); document.write( "22 = 2x + 2(x - 3)\r
\n" ); document.write( "\n" ); document.write( "22 = 2x + 2x - 6\r
\n" ); document.write( "\n" ); document.write( "22 = 4x - 6\r
\n" ); document.write( "\n" ); document.write( "22 + 6 = 4x\r
\n" ); document.write( "\n" ); document.write( "28 = 4x\r
\n" ); document.write( "\n" ); document.write( "28/4 = x\r
\n" ); document.write( "\n" ); document.write( "7 = x\r
\n" ); document.write( "\n" ); document.write( "Since x = length, then length is 7 feet.\r
\n" ); document.write( "\n" ); document.write( "Our width is x - 3.\r
\n" ); document.write( "\n" ); document.write( "Replacing x with 7 and subtracting 3, will give us 4 feet.\r
\n" ); document.write( "\n" ); document.write( "Final answer: width = 4 feet and length = 7 feet. \r
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