document.write( "Question 165667: justin earns scores of 75,83,77,and 81 on his first four exams in math class. the final exam is worth twice a regular exam(twice the weight). he wants to earn a B, so he needs at least an 80 average. solve the following equation to find the lowest score he can earn and still get his B!\r
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document.write( "(75+83+77+81+2x) /6 =80\r
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document.write( "I must show my work and i don't know how ???? please help me !!!!! \n" );
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Algebra.Com's Answer #122130 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (75+83+77+81+2x) /6 >=80 \n" ); document.write( "Multiply both sides by 6 to get: \n" ); document.write( "316 + 2x >= 480 \n" ); document.write( "2x >= 164 \n" ); document.write( "x >= 82 \n" ); document.write( "=================== \n" ); document.write( "Chers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |