document.write( "Question 165518: We have 20% alcohol solution and a 50% solution. How many pints must be used from each to obtain 8 pints of a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #122122 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .20x+.50(8-x)=.30*8 \n" ); document.write( ".20x+4-.50x=2.4 \n" ); document.write( "-.30x=2.4-4 \n" ); document.write( "-.30x=-1.6 \n" ); document.write( "x=-1.6/-.30 \n" ); document.write( "x=5.333 pints of 20% are used. \n" ); document.write( "8-5.333=2.667 pints of 50% are used. \n" ); document.write( "Proof: \n" ); document.write( ".20*5.333+.50*2.667=2.4 \n" ); document.write( "1.0666+1.333=2.4 \n" ); document.write( "2.4=2.4 \n" ); document.write( " \n" ); document.write( " |