document.write( "Question 165655: Eleanor invests $18,000 in two funds paying 9 1/4% and 10 1/2% simple interest. How much is invested at each rate if the total yearly interest is $1827.50? \n" ); document.write( "

Algebra.Com's Answer #122114 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "Let $\"x\"$ =amount invt. @ 10-1/2%
\n" ); document.write( "So, $\"18000-x\"$ = amount invt. @ 9-1/4%
\n" ); document.write( "Showing into eqn. with simple interest:
\n" ); document.write( " $\"0.105%28x%29%2B0.0925%2818000-x%29=1827.50\"$
\n" ); document.write( " $\"0.105x%2B1665-0.0925x=1827.50\"$
\n" ); document.write( " $\"0.0125x=1827.50-1665=162.50\"$
\n" ); document.write( " $\"cross%280.0125%29x%2Fcross%280.0125%29=cross%28162.50%2913000%2Fcross%280.0125%29\"$
\n" ); document.write( " $\"x=13000\"$ -----------------> amount invt. @ 10-1/2%
\n" ); document.write( " $\"18000-13000=5000\"$ --------> amount invt. @ 9-1/4%
\n" ); document.write( "It make sense to invest more at higher interest I guess.
\n" ); document.write( "Check,
\n" ); document.write( " $\"0.105%2813000%29%2B0.0925%285000%29=1827.50\"$
\n" ); document.write( " $\"1365%2B462.50=1827.50\"$
\n" ); document.write( " $\"1827.50=1827.50\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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