document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165650>Question 165650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation:<BR>\n" );
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document.write( "     A merchant wishes to mix two grades of coffee, one of which sells for $0.80 per pound and one of which sells for $1.20 per pound. He wants to sell the mixture $1.10 per pound. If he has 25 pounds of the $0.80 coffee, how much of the $1.20 per pound coffee must he add so that the value of the final mixture is equal to the total value of the other two? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122111 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .8*25+1.20x=1.10(25+x)<BR>\n" );
document.write( "20+1.20x=27.5+1.10x<BR>\n" );
document.write( "1.20x-1.10x=27.5-20<BR>\n" );
document.write( ".10x=7.5<BR>\n" );
document.write( "x=7.5/.1<BR>\n" );
document.write( "x=75 pounds of $1.20 coffee is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "20+1.20*75=1.10(25+75)<BR>\n" );
document.write( "20+90=1.10*100<BR>\n" );
document.write( "110=110\r<BR>\n" );
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