document.write( "Question 157358: My daughter has 2 homework problems that she asked for my help on but I am stumped. The directions are to add 3 terms to each pattern and then write an algebraic expression that describes the pattern. She can add the terms to the pattern (see the last 3 numbers in each line below) but we are stumped on the expression that goes with it.\r
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document.write( "Number 1 - 1, 8, 27, 64, 125, 216, 343
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document.write( "Number 2 - 2, 5, 14, 41, 122, 365, 1094\r
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document.write( "Thanks for your help! \n" );
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Algebra.Com's Answer #122110 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Number 1 - 1, 8, 27, 64, 125, 216, 343 \n" ); document.write( "--------------------------- \n" ); document.write( "The numbers above are the cubes of 1, 2, 3, etc. The next 3 terms are 512, 729, 1000. \n" ); document.write( " \n" ); document.write( "Term n = n cubed. \n" ); document.write( "------------------\r \n" ); document.write( "\n" ); document.write( "Number 2 - 2, 5, 14, 41, 122, 365, 1094 \n" ); document.write( "--------------------- \n" ); document.write( "2, 5, 14, 41, 122, 365, 1094 \n" ); document.write( "Each term is the term before it + 3^n \n" ); document.write( "The next 3 terms are 3281, 9842, 29525 \n" ); document.write( "I'll find the algebraic expression later. \n" ); document.write( "----------------- \n" ); document.write( "OK, each term in the sum of n terms of 3 to the power of 1 to n, + 1. \n" ); document.write( "The algebraic for the sum of n terms is: \n" ); document.write( " \n" ); document.write( "Each term is that plus 1, so it's \n" ); document.write( " \n" ); document.write( "It's not simple.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |