document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23397>Question 23397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Give the equation of the line in standard form which is perpendicular to -3x+4y=8 and passes through (-3,5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12211 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12211\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+4y=8 and passes through (-3,5)<BR>\n" );
document.write( "You need to first put the equation in slope-intercept form, <BR>\n" );
document.write( "3x+4Y=8<BR>\n" );
document.write( "4y=-3x+8<BR>\n" );
document.write( "y=-3/4x+8/4<BR>\n" );
document.write( "y=-3/4x+2<BR>\n" );
document.write( "A line is perpendicular when its slopes are negative reciprocals of one another.<BR>\n" );
document.write( "So the line which is perpendicular has a slope of 4/3.<BR>\n" );
document.write( "So you need to plot the point given, then with the slope of 4/3 find the y-intercept then write the new equation.When you graph this line you find your y-intercept to be 1;<BR>\n" );
document.write( "The equation would be;<BR>\n" );
document.write( "y=4/3x+1<BR>\n" );
document.write( "Hope you understand<BR>\n" );
document.write( "=) </SPAN>\n" );
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