document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165650>Question 165650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation:<BR>\n" );
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document.write( "     A merchant wishes to mix two grades of coffee, one of which sells for $0.80 per pound and one of which sells for $1.20 per pound. He wants to sell the mixture $1.10 per pound. If he has 25 pounds of the $0.80 coffee, how much of the $1.20 per pound coffee must he add so that the value of the final mixture is equal to the total value of the other two? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122109 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A merchant wishes to mix two grades of coffee, one of which sells for $0.80 per pound and one of which sells for $1.20 per pound. He wants to sell the mixture $1.10 per pound. If he has 25 pounds of the $0.80 coffee, how much of the $1.20 per pound coffee must he add so that the value of the final mixture is equal to the total value of the other two?<BR>\n" );
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document.write( "80 cent coffee DATA:<BR>\n" );
document.write( "Amt. = 25 lbs. ; value = 80*25 = 2000 cents<BR>\n" );
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document.write( "120 cent coffee DATA:<BR>\n" );
document.write( "Amt = x lbs. ; value = 120x cents<BR>\n" );
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document.write( "110 cent coffee DATA:<BR>\n" );
document.write( "Amt = 25+x lbs value = 110(25+x)<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "2000 + 120x = 110(25+x)<BR>\n" );
document.write( "2000 + 120x = 2750 + 110x<BR>\n" );
document.write( "10x = 750<BR>\n" );
document.write( "x = 75 lbs (amount of $1.20 coffee needed for the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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