document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165604>Question 165604</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of a parabola that:<BR>\n" );
document.write( "A. has x=3 as its axis of symmetry and passes through the points (2,5) & (-1,-25).<BR>\n" );
document.write( "B. passes through the points (-3,2), (-2,8), and (1,2).\r<BR>\n" );
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document.write( "PLEASE show any graphical or algebraic support needed to provide the solution!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122104 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the vertex form of the parabola equation is y=a(x-h)^2+k, where (h,k) is the vertex<BR>\n" );
document.write( "__ the axis of symmetry goes through the vertex\r<BR>\n" );
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document.write( "A. substituting __ 5=a(2-3)^2+k __ 5=a+k<BR>\n" );
document.write( "__ substituting __ -25=a(-1-3)^2+k __ -25=16a+k\r<BR>\n" );
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document.write( "subtracting the equations __ -25-5=16a+k-a-k __ -30=15a __ -2=a\r<BR>\n" );
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document.write( "substituting __ 5=(-2)+k __ 7=k\r<BR>\n" );
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document.write( "y=-2(x-3)^2+7\r<BR>\n" );
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document.write( "B.the points (-3,2) and (1,2) have the same y value, so the axis of symmetry is midway between them __ x=-1\r<BR>\n" );
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document.write( "substituting __ 2=a(-3+1)^2+k __ 2=4a+k\r<BR>\n" );
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document.write( "substituting __ 8=a(-2+1)^2+k __ 8=a+k\r<BR>\n" );
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document.write( "subtracting the equations __ 2-8=4a+k-a-k __ -6=3a __ -2=a\r<BR>\n" );
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document.write( "substituting __ 8=(-2)+k __ 10=k\r<BR>\n" );
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document.write( "y=-2(x+1)^2+10 </SPAN>\n" );
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