document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165639>Question 165639</A>: <I><SPAN STYLE=\"word-break: break-all;\">  HEY, how would you solve 3(p+1)^2=81??<BR>\n" );
document.write( "and 5y^2+4=14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122095 by </B><A HREF=/tutors/aboutme.mpl?userid=NerdvanaGirl><B>NerdvanaGirl(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=NerdvanaGirl><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For 3(p+1)^2=81<BR>\n" );
document.write( "I would start by dividing both sides by 3<BR>\n" );
document.write( "Therefore (p+1)^2=81/3 or (p+1)^2 = 27<BR>\n" );
document.write( "I would then take the square root of each side<BR>\n" );
document.write( "p+1 = radical 27<BR>\n" );
document.write( "Then subtract 1<BR>\n" );
document.write( "p=(radical 27) - 1 or p = -1 + (radical 27) or punch in radical 27 into a calculator and then subtract 1, which is 5.1961524 - 1 = approximately 4.196\r<BR>\n" );
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document.write( "For 5y^2+4=14 <BR>\n" );
document.write( "I would first subtract 4<BR>\n" );
document.write( "so 5y^2=10<BR>\n" );
document.write( "Then divide by 5<BR>\n" );
document.write( "y^2=2<BR>\n" );
document.write( "Take the square root<BR>\n" );
document.write( "y= radical 2 or y= approximately 1.41421 </SPAN>\n" );
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