document.write( "Question 165631: Can someone please explain to me how to do this problem?\r
\n" ); document.write( "\n" ); document.write( "Find the domain of the rational expression.\r
\n" ); document.write( "\n" ); document.write( "f(x)=3x+1
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\n" ); document.write( " x-5\r
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Algebra.Com's Answer #122086 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"f%28x%29=%283x%2B1%29%2F%28x-5%29\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"x-5=0\" Set the denominator equal to zero. Remember, dividing by 0 is undefined. So if we find values of x that make the denominator zero, then we must exclude them from the domain.\r
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\n" ); document.write( "\n" ); document.write( "\"x=0%2B5\"Add 5 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=5\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "Since \"x=5\" makes the denominator equal to zero, this means we must exclude \"x=5\" from our domain\r
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\n" ); document.write( "\n" ); document.write( "So our domain is: \r
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\n" ); document.write( "\n" ); document.write( "which in plain English reads: x is the set of all real numbers except x CANNOT equal \"5\"\r
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\n" ); document.write( "\n" ); document.write( "So our domain looks like this in interval notation\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the parenthesis excludes 5 from the domain\r
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\n" ); document.write( "\n" ); document.write( "If we wanted to graph the domain on a number line, we would get:\r
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\n" ); document.write( "\n" ); document.write( " Graph of the domain in blue and the excluded value represented by open circle\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a continuous line until we get to the hole at \"x=5\" (which is represented by the open circle).
\n" ); document.write( "This graphically represents our domain in which x can be any number except x cannot equal 5
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