document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165624>Question 165624</A>: <I><SPAN STYLE=\"word-break: break-all;\"> donna invested her $33000.00 bonus and received a total of $970.00 in interest after one year. if part of the money returned 4% and the remainder 2.25%, then how much did she invest at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122076 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> well there are two amounts we are dealing with here that total $33000. so we will call one amount x and the other 33000-x.  the total of the two principal sums times there various interest rates will equal the interest earned.\r<BR>\n" );
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document.write( "so we have .04x+.0225(33000-x)=970  distribute the 2nd term and we get\r<BR>\n" );
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document.write( ".04x+742.50-.0225x=970 simply to .0125x=227.5  x=$18200 ...  $33000-x=$14800\r<BR>\n" );
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document.write( "so Donna invested $18,200 at 4% and $14,200 at 2.25% </SPAN>\n" );
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