document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165606>Question 165606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jasmine has three more nickles then dimes. There are 25 coins all togther. How many of each coin is there. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122064 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n=Nickels d=dimes  so n=d+3  and n+d=25 so substituting n's value from the 1st equation into the 2nd equation we get    (d+3)+d=25 or 2d+3=25 and subtracting 3 from each side we get 2d=22  so d=11 and since n=d(11)=3 then n=14\r<BR>\n" );
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document.write( "so there are 14 nickels and 11 dimes </SPAN>\n" );
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