document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165593>Question 165593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, if theta is an acute angle and sin theta =1/2, then cos theta=\r<BR>\n" );
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document.write( "I have drawn a right triangle with the hypotenus on the right. It has a one on the bottom and a two on the hypotenuse.  Then I tried 1^2+b^2=2^2 and ended up with square root of b^2 =square root of 3.  I do not know where to go from there<BR>\n" );
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document.write( "Thankyou. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122060 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have done ok so far!<BR>\n" );
document.write( "In your triangle, you have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a+=+1 ALIGN=MIDDLE  ALT=\"a+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c+=+2 ALIGN=MIDDLE  ALT=\"c+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+sqrt%283%29 ALIGN=MIDDLE  ALT=\"b+=+sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "To see how we get b, you have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2+=+3 ALIGN=MIDDLE  ALT=\"b%5E2+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+sqrt%283%29 ALIGN=MIDDLE  ALT=\"b+=+sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The sin of theta (I'll call it A because I can't do a theta symbol) is given as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > because the sine of the angle is the side opposite the angle (a = 1) over the hypotenuse (c = 2), so you get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%28A%29+=+1%2F2 ALIGN=MIDDLE  ALT=\"sin%28A%29+=+1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The cosine of this angle (A) is the side adjacent to the angle (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+sqrt%283%29 ALIGN=MIDDLE  ALT=\"b+=+sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > over the hypotenuse (c = 2), so...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cosin%28A%29+=+sqrt%283%29%2F2 ALIGN=MIDDLE  ALT=\"cosin%28A%29+=+sqrt%283%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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