document.write( "Question 165510: The shape of a supporting arch can be modeled by h(x)=-0.03x^2+3x, where h(x) represents the height of the arch and x represents the horizontal distance from one end of the base of the arch in meters. Find the maximum height of the arch. Show work.
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Algebra.Com's Answer #122056 by ankor@dixie-net.com(22740)\"\" \"About 
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The shape of a supporting arch can be modeled by h(x)=-0.03x^2+3x, where h(x) represents the height of the arch and x represents the horizontal distance from one end of the base of the arch in meters.
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\n" ); document.write( "Solve the equation for x = 0;
\n" ); document.write( "-.03x^2 + 3x = 0
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\n" ); document.write( "Factor out -.03x
\n" ); document.write( "-.03x(x - 100) = 0
\n" ); document.write( "x = 0
\n" ); document.write( "and
\n" ); document.write( "x = 100 meters is the width of the base of the arch
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\n" ); document.write( "Find the maximum height of the arch.
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\n" ); document.write( "Max height occurs halfway, at x = 50 (axis of symmetry)
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\n" ); document.write( "Substitute 50 for x in the original equation
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\n" ); document.write( "h(x) = -.03*50^2 + 3(50) = 0
\n" ); document.write( "h(x) = -75 + 150
\n" ); document.write( "h(x) = 75 meters is the height \n" ); document.write( "
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