document.write( "Question 165538: how do i factor a quadratic equation and apply the zero product rule to find the solution set? \n" ); document.write( "
Algebra.Com's Answer #122051 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Here's an example.
\n" ); document.write( "\"x%5E2%2B3x%2B2=0\"
\n" ); document.write( "You can factor the quadratic equation.
\n" ); document.write( "\"%28x%2B2%29%28x%2B1%29=0\"
\n" ); document.write( "Zero product rule says either the first factor or the second factor could equal zero so solve for both.
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\n" ); document.write( "First factor:
\n" ); document.write( "\"x%2B2=0\"
\n" ); document.write( "\"x=-2\"
\n" ); document.write( "Second factor:
\n" ); document.write( "\"x%2B1=0\"
\n" ); document.write( "\"x=-1\"
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\n" ); document.write( "The solution set (zeros) for the equation are x=-1,-2.
\n" ); document.write( "You can check the answers by plugging into the equation or you could graph the equation to verify.
\n" ); document.write( "\"x%5E2%2B3x%2B2=0\"
\n" ); document.write( "\"%28-2%29%5E2%2B3%28-2%29%2B2=0\"
\n" ); document.write( "\"4-6%2B2=0\"
\n" ); document.write( "\"0=0\"
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\n" ); document.write( "\"+graph%28+300%2C+300%2C+-3%2C+1%2C+-3%2C1%2C++x%5E2%2B3x%2B2%29+\"
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