document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23432>Question 23432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> warren has 40 coins all nickles, dimes, and quarters worth 4.05$.  He has seven more nickles then dimes how many quarters.\r<BR>\n" );
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document.write( "Lori clames she has 20.00$ in quarters ,half dollars, and one dollar bills.  She has twice as many quarters as half dollars and Half as many one dollar biils as Half dollars.  Give an argument as to why this is wrong. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12204 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let dimes be x<BR>\n" );
document.write( "Let nickels be 7+x<BR>\n" );
document.write( "Let quarters be y<BR>\n" );
document.write( "7+x+x+y=40<BR>\n" );
document.write( "y=33-2x\r<BR>\n" );
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document.write( "5(7+x)+10(x)+25(33-2x)=405<BR>\n" );
document.write( "35+5x+10x+825-50x=405<BR>\n" );
document.write( "-35x=-455<BR>\n" );
document.write( "x=13<BR>\n" );
document.write( "13+7=20\r<BR>\n" );
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document.write( "20+13=33, 40-33=7\r<BR>\n" );
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document.write( "Hence he has 13 dimes, 20 nickels and 7 quartes\r<BR>\n" );
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document.write( "Check: 10(13)+5(20)+25(7)<BR>\n" );
document.write( "130+100+175=405<BR>\n" );
document.write( "405/100 = $4.05 </SPAN>\n" );
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