document.write( "Question 165572: if jeanne can type 20 pages in 40 minutes and jim can type 20 pages in 30 minutes, how long will it take them to type 20 pages working together? \n" ); document.write( "

Algebra.Com's Answer #122033 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x=time it takes to type 20 pages when both are working together
\n" ); document.write( "So, 20/x=rate at which they work when working together
\n" ); document.write( "Jeanne types at the rate of 20/40=1/2 page per min
\n" ); document.write( "Jim types at the rate of 20/30=2/3 pages per min\r
\n" ); document.write( "\n" ); document.write( "Together they work at the rate of 1/2 + 2/3 =7/6 pages per min
\n" ); document.write( "So, our equation to solve is:
\n" ); document.write( "(7/6)*x=20 multiply each side by6
\n" ); document.write( "7x=120
\n" ); document.write( "x=17.143 min\r
\n" ); document.write( "\n" ); document.write( "Another way:
\n" ); document.write( "7/6=20/x multiply each side by 6x
\n" ); document.write( "7x=120-----------same as before\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "(1/2)*17.143= 8.571 pages
\n" ); document.write( "(2/3)*17.143=11.429 pages
\n" ); document.write( "8.571 + 11.429=20
\n" ); document.write( "20=20\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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