document.write( "Question 165535: Use the substitution method to solve the systems of equations.\r
\n" ); document.write( "\n" ); document.write( "2x+y=4
\n" ); document.write( "2x-y=0\r
\n" ); document.write( "\n" ); document.write( "I am racking my brain on this one! thanks in advance for any help you would be able to give me!
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Algebra.Com's Answer #122008 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++2%5Cx+%2B+1%5Cy+=+4%2C%0D%0A++++2%5Cx+%2B+-1%5Cy+=+0+%29%0D%0A++\"We'll use substitution. After moving 1*y to the right, we get:
\n" ); document.write( " \"2%2Ax+=+4+-+1%2Ay\", or \"x+=+4%2F2+-+1%2Ay%2F2\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"2%2A%284%2F2+-+1%2Ay%2F2%29+%2B+-1%5Cy+=+0\" and simplify: So, we know that y=2. Since \"x+=+4%2F2+-+1%2Ay%2F2\", x=1.
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\n" ); document.write( " Answer: \"system%28+x=1%2C+y=2+%29\".
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