document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165521>Question 165521</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please explain how to reverse the FOIL method when factoring a polynomial of the form ax^2+bx+c when a=1. Please give an example so that I might understand better. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122001 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122001\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> start with two binomials, x+j and x+k\r<BR>\n" );
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document.write( "FOILing gives __ x^2+kx+jx+kj __ x^2+(k+j)x+kj\r<BR>\n" );
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document.write( "the factors of the c term are k and j __ the sum of those factors is the b term\r<BR>\n" );
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document.write( "reverse FOILing is finding factors of c that sum to b\r<BR>\n" );
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document.write( "EX. __ x^2-5x+6 __ factors of 6 are (±1, ±6) and (±2, ±3)<BR>\n" );
document.write( "__ -2 plus -3 is -5<BR>\n" );
document.write( "__ x^2-5x+6=(x-2)(x-3) </SPAN>\n" );
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