document.write( "Question 165493: the sum of the square of the two consecutive odd intergers is equal to 290 find the two intergers \n" ); document.write( "

Algebra.Com's Answer #121988 by jojo14344(1513) $\"\"$ $\"About$

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\n" ); document.write( "Two consecutive ODD Integers ---- $\"system%28x%2Cx%2B2%29\"$
\n" ); document.write( "Condition:
\n" ); document.write( " $\"x%5E2%2B%28x%2B2%29%5E2=290\"$ , EQN 1
\n" ); document.write( "Continuing,
\n" ); document.write( " $\"x%5E2%2Bx%5E2%2B4x%2B4=290\"$
\n" ); document.write( " $\"2x%5E2%2B4x%2B4-290\"$ ---> $\"2x%5E2%2B4x-286=0\"$ , divide whole eqn by 2
\n" ); document.write( "
\n" ); document.write( " $\"x%5E2%2B2x-143-0\"$
\n" ); document.write( "Remember --- $\"system%28a=1%2Cb=2%2Cc=-143%29\"$
\n" ); document.write( "By PYTH.THEOREM:
\n" ); document.write( " $\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( " $\"x=%28-2%2B-sqrt%282%5E2-4%281%29%28-143%29%29%29%2F%282%2A1%29\"$
\n" ); document.write( " $\"x=%28-2%2B-sqrt%284%2B572%29%29%2F2\"$
\n" ); document.write( " $\"x=%28-2%2B-sqrt%28576%29%29%2F2\"$ ----> $\"x=%28-2%2B-24%29%2F2\"$
\n" ); document.write( "2 VALUES:
\n" ); document.write( " $\"x=%28-2%2B24%29%2F2=22%2F2\"$
\n" ); document.write( " $\"highlight%28x=11%29\"$
\n" ); document.write( " $\"x=%28-2-24%29%2F2=-26%2F2\"$
\n" ); document.write( " $\"x=-13\"$
\n" ); document.write( "USE HIGHLIGHTED ONE:
\n" ); document.write( " $\"x=11\"$ -------------> 1st odd intgr.
\n" ); document.write( " $\"x%2B2=11%2B2=13\"$ ------> 2nd odd intgr.
\n" ); document.write( "Check via EQN 1,
\n" ); document.write( " $\"11%5E2%2B13%5E2=290\"$
\n" ); document.write( " $\"121%2B169=290\"$
\n" ); document.write( " $\"290=290\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

\n" );