document.write( "Question 165493: the sum of the square of the two consecutive odd intergers is equal to 290 find the two intergers \n" ); document.write( "

Algebra.Com's Answer #121986 by Fombitz(32388) $\"\"$ $\"About$

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Let n be the first integer, (n+2) would be the next consecutive odd integer.
\n" ); document.write( " $\"n%5E2%2B%28n%2B2%29%5E2=290\"$
\n" ); document.write( " $\"n%5E2%2B%28n%5E2%2B4n%2B4%29=290\"$
\n" ); document.write( " $\"2n%5E2%2B4n-286=0\"$
\n" ); document.write( " $\"n%5E2%2B2n-143=0\"$
\n" ); document.write( "You can factor this quadratic equation.
\n" ); document.write( " $\"%28n%2B13%29%28n-11%29=0\"$
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\n" ); document.write( "First solution:
\n" ); document.write( " $\"n%2B13=0\"$
\n" ); document.write( " $\"n=-13\"$
\n" ); document.write( "The two integers are then -13 and -11.
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\n" ); document.write( "Second solution:
\n" ); document.write( " $\"n-11=0\"$
\n" ); document.write( " $\"n=11\"$
\n" ); document.write( "The two integers are then 11 and 13.\r
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