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document.write( "Prove that (1,0,0,1) and (0,1,1,0) are linearly independent. I think they are dependent, am i missing something? \n" );
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Algebra.Com's Answer #121980 by Fombitz(32388) You can put this solution on YOUR website! The previous discussion regarding dot product was not correct. \n" ); document.write( "I mixed up orthogonality and linear independence. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "For these two vectors to be linearly independent, then a combination of these two vectors with two scalar multipliers can only be zero when the multipliers are zero. \n" ); document.write( "(1,0,0,1)A+(0,1,1,0)B=(0,0,0,0) only if A=B=0. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Look at each individual component of the vectors. \n" ); document.write( "1.(1)A+(0)B=0 \n" ); document.write( "2.(0)A+(1)B=0 \n" ); document.write( "3.(0)A+(1)B=0 \n" ); document.write( "4.(1)A+(0)B=0 \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "From 1 and 4, \n" ); document.write( "A=0 \n" ); document.write( "From 2 and 3, \n" ); document.write( "B=0 \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Therefore, you proved that they are linearly independent because the combination of the two vectors can only equal the zero vector when A=B=0. \n" ); document.write( "Sorry for the confusion.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |