document.write( "Question 165469: Find the variation constant, and write a formula that expresses the indicated variation.\r
\n" ); document.write( "\n" ); document.write( "c varies inversely as d, and c  5 when d  2.\r
\n" ); document.write( "\n" ); document.write( "I'm not grasping the concept here, please help.
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Algebra.Com's Answer #121979 by gonzo(654)\"\" \"About 
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* In inverse variation, when one variable increases the other decreases in proportion so that the product remains the same always.
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\n" ); document.write( "your problem states that c varies inversely as d.
\n" ); document.write( "not sure of the symbols, but i understand that part to mean that c = 5 when d = 2.
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\n" ); document.write( "formula for constant of inverse variation is xy = k or x = k/y, or y = k/x
\n" ); document.write( "k is the constant of variation.
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\n" ); document.write( "in your problem, that formula would appear as cd = k, or c = k/d or d = k/c.
\n" ); document.write( "if c is 5, and d is 2, the formula becomes (5*2) = k = 10
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\n" ); document.write( "constant variation appears to be 10.
\n" ); document.write( "c = k/d becomes 5 = 10/2 = 5.
\n" ); document.write( "d = k/c becomes 2 = 10/5 = 2.
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\n" ); document.write( "it works out if i understood your problem correctly.
\n" ); document.write( "k = 10.
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\n" ); document.write( "the formula that expresses this relationship would be cd = 10.
\n" ); document.write( "that would equate to either:
\n" ); document.write( "c = 10/d
\n" ); document.write( "or
\n" ); document.write( "d = 10/c
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