document.write( "Question 23418: Please help me with this question!!! I have NO CLUE what i am doing!! Here is the question: The sum of the squares of two consecutive negative even integers is 100. Find the integers.\r
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Algebra.Com's Answer #12196 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Start by letting x = the first negative even integer. The next consecutive negative even integer is x+2.
\n" ); document.write( "From the problem description, you can write:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+%28x%2B2%29%5E2+=+100\" Simplify and solve for x.
\n" ); document.write( "\"x%5E2+%2B+x%5E2+%2B+4x+%2B+4+=+100\" Subtract 100 from both sides of the equation.
\n" ); document.write( "\"2x%5E2+%2B+4x+-+96+=+0\" Factor out a 2.
\n" ); document.write( "\"2%28x%5E2+%2B+2x+-+48%29+=+0\" Factor the parentheses.
\n" ); document.write( "\"2%28x+-+6%29%28x+%2B+8%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"x+-+6+=+0\" and/or \"x+%2B+8+=+0\"
\n" ); document.write( "If \"x+-+6+=+0\" then \"x+=+6\" Discard this solution...you want negative integers.
\n" ); document.write( "If \"x+%2B+8+=+0\" then \"x+=+-8\" This solution is valid and \"x%2B2+=+-8%2B2\" = \"-6\"\r
\n" ); document.write( "\n" ); document.write( "The two consecutive negative even integers are:\r
\n" ); document.write( "\n" ); document.write( "-8 and -6\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"%28-8%29%5E2+%2B+%28-6%29%5E2+=+64+%2B+36\" = \"100\"
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