document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165431>Question 165431</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 1:30pm Tom leaves in his boat from a dock and heads south at a rate of 25 miles per hour. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If she travels at a rate of 30 miles per hour, when will she catch up to Tom? Write an equation to find the value for Toms Time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121955 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121955\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tom's speed = 25 mph<BR>\n" );
document.write( "Mary's speed = 30 mph\r<BR>\n" );
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document.write( "Let Tom's time = t hours<BR>\n" );
document.write( "so, Mary's time = (t - (10/60)) hours\r<BR>\n" );
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document.write( "when Mary and Tom meets:<BR>\n" );
document.write( "Mary's distance = Tom's distance<BR>\n" );
document.write( "30*(t - 1/6) = 25*t<BR>\n" );
document.write( "<=> 30t - 5 = 25t<BR>\n" );
document.write( "<=> 30t - 25t = 5<BR>\n" );
document.write( "<=> 5t = 5<BR>\n" );
document.write( "<=> t = 5/5 = 1\r<BR>\n" );
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document.write( "so, Mary can catch Tom 1 hour after Tom left,<BR>\n" );
document.write( "that means, she can catch Tom at 2:30pm </SPAN>\n" );
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