document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165423>Question 165423</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534492770/algebrahomeworkh>mathematics for calculus</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> a pharmacist wishes to make 1.8 liters of a 10% solution of boric acid by mixing 7.5% and 12% solutions. How much a each type should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121936 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a pharmacist wishes to make 1.8 liters of a 10% solution of boric acid by mixing 7.5% and 12% solutions. How much a each type should be used?<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.075x + 0.12(1.8-x) = 0.10(1.8)<BR>\n" );
document.write( "Multiply thru by 1000 to get:<BR>\n" );
document.write( "75x + 120*1.8-120x = 100*1.8<BR>\n" );
document.write( "-45x = -20*1.8<BR>\n" );
document.write( "x = 0.8 liters (amount of 7.5% solution in the mixture)<BR>\n" );
document.write( "1.8-0.8 = 1 liter ( amount of 12% solution in the mixture)<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );