document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165401>Question 165401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Below are the equations that I need assistance with...\r<BR>\n" );
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document.write( "1. 2x+y-3z=-4\r<BR>\n" );
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document.write( "2. 4x-2y+z=9\r<BR>\n" );
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document.write( "3. 3x+5y-3z=5\r<BR>\n" );
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document.write( "Below are the instructions to solving the problems. I am supposed to solve for x, y, and z. The answer should be the same for x, y, and z in all three equations. For instance, if x is 2, y is 5, and z is 3 in problem #1, the answer should be the same for the last two problems. My professor explained this to me, but when I tried to solve it, I did not receive the correct answer. Please help me. I would really appreciate it. I need this answer for my class as soon as possible...\r<BR>\n" );
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document.write( "1.Choose two of the three equations so that one of the variables is eliminated (use addition method).\r<BR>\n" );
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document.write( "2.Repeat step one with two different equations to eliminate the same variable.\r<BR>\n" );
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document.write( "3.Use the equation resulting from steps 1 & 2 to solve for one of the variables.\r<BR>\n" );
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document.write( "4.Substitute the variable in step 3 into equation to solve for a second variable.\r<BR>\n" );
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document.write( "5.Substitute the values from steps 3&4 into equations 1, 2, or 3 to solve for the final variable. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121934 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. 2x+y-3z=-4 <BR>\n" );
document.write( "2. 4x-2y+z=9 <BR>\n" );
document.write( "3. 3x+5y-3z=5<BR>\n" );
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document.write( "Multiply eqn 2 by 3<BR>\n" );
document.write( "12x-6y+3z=27<BR>\n" );
document.write( "Add to eqn 1 and to eqn 3<BR>\n" );
document.write( "1. 2x+y-3z=-4 <BR>\n" );
document.write( " 12x-6y+3z=27<BR>\n" );
document.write( " 14x-5y = 23  No z term<BR>\n" );
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document.write( "3. 3x+5y-3z=5<BR>\n" );
document.write( " 12x-6y+3z=27<BR>\n" );
document.write( " 15x-y = 32  No z here either<BR>\n" );
document.write( "Now there are 2 eqns in 2 unknowns:<BR>\n" );
document.write( "14x-5y = 23<BR>\n" );
document.write( "15x- y = 32  Multiply this by 5 to get the same y coefficient<BR>\n" );
document.write( "75x-5y = 160<BR>\n" );
document.write( "14x-5y = 23  Subtract this from it<BR>\n" );
document.write( "61x = 137<BR>\n" );
document.write( "x = 137/61  Answer for x<BR>\n" );
document.write( "Sub x into 15x -y = 32<BR>\n" );
document.write( "15*(137/61) - y = 32<BR>\n" );
document.write( "y = (15*137 - 32*61)/61<BR>\n" );
document.write( "y = 103/61  Answer for y<BR>\n" );
document.write( "Sub x and y into any of the 3 original eqns, I'll use #1<BR>\n" );
document.write( "1. 2x+y-3z=-4 <BR>\n" );
document.write( "2*(137/61) + (103/61) - 3z = -244/61<BR>\n" );
document.write( "-3z = (-244 - 274 - 103)/61<BR>\n" );
document.write( "-3z = -621/61<BR>\n" );
document.write( "z = 207/61<BR>\n" );
document.write( " </SPAN>\n" );
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