document.write( "Question 23409: I need your help with this problem. \r
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document.write( "A boat traveled 96 miles in 8 hours against the current. The boat returned to its starting point following the saame course traveling with the current. The return trip took 5 hours. What is the speed of the current and the speed of the boat in still water? \n" );
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Algebra.Com's Answer #12193 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let y be the current and let x be the boat;s speed \n" ); document.write( "8(x-y)=96 -----> 8x-8y=96 (equation 1 ) \n" ); document.write( "5(x+y)=96 -----> 5x+5y=96 (equation 2 )\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Mutliply equation 1 by 5 -----> 40x-40y=480 \n" ); document.write( "Multiply equation 2 by 8 -----> 40x+40y=768 \n" ); document.write( "Add the equations:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "80x=1248 \n" ); document.write( "x=15.6\r \n" ); document.write( "\n" ); document.write( "5(15.6)+5y=96 \n" ); document.write( "78+5y=96 \n" ); document.write( "5y=18 \n" ); document.write( "y=3.6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence the speed of the boat is 15.6mph and the speed of the current is 3.6mph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |