document.write( "Question 23409: I need your help with this problem. \r
\n" ); document.write( "\n" ); document.write( "A boat traveled 96 miles in 8 hours against the current. The boat returned to its starting point following the saame course traveling with the current. The return trip took 5 hours. What is the speed of the current and the speed of the boat in still water?
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Algebra.Com's Answer #12193 by Paul(988)\"\" \"About 
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Let y be the current and let x be the boat;s speed
\n" ); document.write( "8(x-y)=96 -----> 8x-8y=96 (equation 1 )
\n" ); document.write( "5(x+y)=96 -----> 5x+5y=96 (equation 2 )\r
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\n" ); document.write( "\n" ); document.write( "Mutliply equation 1 by 5 -----> 40x-40y=480
\n" ); document.write( "Multiply equation 2 by 8 -----> 40x+40y=768
\n" ); document.write( "Add the equations:\r
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\n" ); document.write( "\n" ); document.write( "80x=1248
\n" ); document.write( "x=15.6\r
\n" ); document.write( "\n" ); document.write( "5(15.6)+5y=96
\n" ); document.write( "78+5y=96
\n" ); document.write( "5y=18
\n" ); document.write( "y=3.6\r
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\n" ); document.write( "\n" ); document.write( "Hence the speed of the boat is 15.6mph and the speed of the current is 3.6mph.\r
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