document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165424>Question 165424</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"If 2/3 of a number is added to the number, the result is 110. Find the numbers\"\r<BR>\n" );
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document.write( "My solution:\r<BR>\n" );
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document.write( "2/3 = 67%<BR>\n" );
document.write( "110 x 67% = 73.7<BR>\n" );
document.write( "110 - 73.7 = 36.3\r<BR>\n" );
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document.write( "or\r<BR>\n" );
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document.write( "110 / 3 = 36.67\r<BR>\n" );
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document.write( "Therefore 2/3 would be 73.34 + 36. 67 = 110\r<BR>\n" );
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document.write( "Would both be correct, or neither?\r<BR>\n" );
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document.write( "Thank you very much in advance. The tutors are very much appreciated for their time and knowledge! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121929 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/3x +x=110 where x is the given number. remember how its stated two thirds of a number(x) which would be 2/3x is added to itself (x), that is how I arrived at the equation. Then it is a simple matter of solving for x.   so (5/3)x=110 so 5x=330 and x=66\r<BR>\n" );
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document.write( "hope that helps!!!!! </SPAN>\n" );
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