document.write( "Question 165413This question is from textbook
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document.write( ": Two ships leave port, one sailing east and the other south. Some time later they are 17 mi apart, with the eastbound ship 7 mi farther from port than the southbound ship. How far is each from port? \n" );
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Algebra.Com's Answer #121917 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two ships leave port, one sailing east and the other south. Some time later they are 17 mi apart, with the eastbound ship 7 mi farther from port than the southbound ship. How far is each from port? \n" ); document.write( ": \n" ); document.write( "This is a right triangle problem \n" ); document.write( ": \n" ); document.write( "Let x = distance from port of the southbound ship (one side of a right triangle) \n" ); document.write( "then \n" ); document.write( "(x+7) = distance from port of the eastbound ship (2nd side of a right triangle) \n" ); document.write( ": \n" ); document.write( "Distance between them = 17 mi (hypotenuse of the triangle) \n" ); document.write( ": \n" ); document.write( "x^2 + (x+7)^2 = 17^2 \n" ); document.write( ": \n" ); document.write( "x^2 + x^2 + 14x + 49 = 289 \n" ); document.write( ": \n" ); document.write( "2x^2 + 14x + 49 - 289 = 0 \n" ); document.write( ": \n" ); document.write( "2x^2 + 14x - 240 = 0 \n" ); document.write( "Simplify, divide equation by 2 \n" ); document.write( "x^2 + 7x - 120 = 0 \n" ); document.write( "Factor \n" ); document.write( "(x-8)(x-15) = 0 \n" ); document.write( "Positive solution \n" ); document.write( "x = 8 distance from port of the southbound ship \n" ); document.write( "and \n" ); document.write( "8 + 7 = 15 mi distance of the eastbound ship \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check on calc enter: sqrt(8^2+15^2) = 17 \n" ); document.write( " |