document.write( "Question 165380: If the police have 7 suspects, how many different ways can they select 5 for a lineup? \n" ); document.write( "
Algebra.Com's Answer #121907 by nerdybill(7384)\"\" \"About 
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If the police have 7 suspects, how many different ways can they select 5 for a lineup?
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\n" ); document.write( "Since it doesn't matter which order the suspects line up, it is a \"combination\" as opposed to a \"permutation\".
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\n" ); document.write( "Combination:
\n" ); document.write( "nCr = (n!)/[r!(n-r)!]
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\n" ); document.write( "In our case:
\n" ); document.write( "n = 7
\n" ); document.write( "r = 5
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\n" ); document.write( "nCr = (7!)/[5!(7-5)!]
\n" ); document.write( "nCr = (7!)/[5!(2)!]
\n" ); document.write( "nCr = (1*2*3*4*5*6*7)/[(1*2*3*4*5)(1*2)]
\n" ); document.write( "Canceling like-terms:
\n" ); document.write( "nCr = (6*7)/[(1*2)]
\n" ); document.write( "nCr = (42)/(2)
\n" ); document.write( "nCr = 21\r
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