document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165382>Question 165382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 57.The first side is twice the length of the second side.The third side is seven more than the second side.What is the length of each side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121900 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A+B+C=57  A=2B  and C=B+7  so substituting A=2B and C=B+7 into the 1st equation we get (2B)+B+(B+7)=57  so 4B=50   B=12.5  so A=2(12.5)=25 and C=12.5+7=19.5\r<BR>\n" );
document.write( "\n" );
document.write( "So sides are 12.5,19.5,25 in length   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );