document.write( "Question 21609: ted runs two thirds as fast as frank. in two hours frank runs eight miles farther then ted. how fast does each run? \n" ); document.write( "
Algebra.Com's Answer #12186 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Ted data: \n" ); document.write( " distance = d; rate = (2/3)x; time= 2 hr. \n" ); document.write( "Frank data: \n" ); document.write( " distance = d+8; rate = x; time = 2hr. \n" ); document.write( "Formula: distance = rate*time \n" ); document.write( " EQUATION: \n" ); document.write( " Frank distance = Ted distance + 8 \n" ); document.write( " 2x = (4/3)x+8 \n" ); document.write( " 6x = 4x+24 \n" ); document.write( " 2x = 24 \n" ); document.write( " x = 12 mph (rate for Frank) \n" ); document.write( " (2/3)x= 8 mph (rate for Ted)\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |