document.write( "Question 165290: f(x)=4x^3-3x^2+2x-1. Find f(1+2i). Please help me out, I really don't have any idea on what to do!!! \n" ); document.write( "
Algebra.Com's Answer #121859 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Note: it's helpful to remember that \"i%5E2=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=4x%5E3-3x%5E2%2B2x-1\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%2B2i%29=4%281%2B2i%29%5E3-3%281%2B2i%29%5E2%2B2%281%2B2i%29-1\" Plug in \"x=1%2B2i\". In other words, replace each \"x\" with \"1+2i\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%2B2i%29=4%281%2B2i%29%5E2%281%2B2i%29-3%281%2B2i%29%5E2%2B2%281%2B2i%29-1\" Break up \"%281%2B2i%29%5E3\" to get \"%281%2B2i%29%5E2%281%2B2i%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%2B2i%29=4%28-3%2B4i%29%281%2B2i%29-3%28-3%2B4i%29%2B2%281%2B2i%29-1\" FOIL \"%281%2B2i%29%5E2\" to get \"1%2B4i%2B4i%5E2=1%2B4i%2B4%28-1%29=-3%2B4i\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%2B2i%29=4%28-11-2i%29-3%28-3%2B4i%29%2B2%281%2B2i%29-1\" FOIL \"%28-3%2B4i%29%281%2B2i%29\" to get \"%28-3%2B4i%29%281%2B2i%29=-3-2i%2B8i%5E2=-3-2i%2B8%28-1%29=-11-2i\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%2B2i%29=-44-8i%2B9-12i%2B2%2B4i-1\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%2B2i%29=-34-16i\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"f%281%2B2i%29=-34-16i\"
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