document.write( "Question 165302: There were 10 more reds than 8 times the number of blues. Also, the number of reds was 5 less tahn 11 times the number of blues. How many of each were there? \n" ); document.write( "
Algebra.Com's Answer #121856 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! B=blue R=Red R=8B+10 R=11B-5 so substituting (8B+10)=11B-5 subtract 8B and add 5 to each side and you get 3B=15 B=5 so R= 8(5)+10=50\r \n" ); document.write( "\n" ); document.write( "Blue=5 \n" ); document.write( "Red =50 \n" ); document.write( " |