document.write( "Question 165302: There were 10 more reds than 8 times the number of blues. Also, the number of reds was 5 less tahn 11 times the number of blues. How many of each were there? \n" ); document.write( "
Algebra.Com's Answer #121855 by gonzo(654)\"\" \"About 
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There were 10 more reds than 8 times the number of blues.
\n" ); document.write( "R = 8*B + 10 (first equation)
\n" ); document.write( "Also, the number of reds was 5 less tahn 11 times the number of blues.
\n" ); document.write( "R = 11*B - 5 (second equation)
\n" ); document.write( "since they both = R, then they are equal to each other.
\n" ); document.write( "8*B + 10 = 11*B - 5
\n" ); document.write( "subtract 8*B from both sides.
\n" ); document.write( "10 = 3*B - 5
\n" ); document.write( "add 5 to both sides.
\n" ); document.write( "15 = 3*B
\n" ); document.write( "divide both sides by 3.
\n" ); document.write( "5 = B
\n" ); document.write( "substitute for B in first equation.
\n" ); document.write( "R = 8*5 + 10
\n" ); document.write( "R = 40 + 10
\n" ); document.write( "R = 50
\n" ); document.write( "substitute for R and B in second equation.
\n" ); document.write( "50 = 11*5 - 5
\n" ); document.write( "50 = 55 - 5
\n" ); document.write( "50 = 50
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\n" ); document.write( "R = 50
\n" ); document.write( "B = 5
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