document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165190>Question 165190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 94.  Marginal revenue.  A defense attorney charges her client $4,000 plus $120 per hour.  The formula R = 120n + 4000 gives her revenue in dollars for n hours of work.  What is her revenue for 100 hours of work?  What is her revenue for 101 hours of work?  By how much did the one extra hour of work increase the revenue?  (The increase in revenue is called the marginal revenue for the 101st hour.)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121847 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121847\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> R = 120n + 4000<BR>\n" );
document.write( "For 100 hours of work?<BR>\n" );
document.write( "R=120(100)+4000=12000+4000=16000<BR>\n" );
document.write( "For 101 hours of work?<BR>\n" );
document.write( "R=120(101)+4000 = 12120+4000 = 16120<BR>\n" );
document.write( "Increase = 120<BR>\n" );
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