document.write( "Question 165223: Find the perimeter and the area of the shaded region use 3.14 for pie.
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document.write( "A retangle shaded with a half circle on one end. The width is 25 ft. the height is 20 ft. I have the answers but I need to know how to work the problem. \r
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document.write( "Answer: Perimeter = 101.4 ft
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document.write( " Area = 343 ft2\r
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document.write( "Can someone please help by showing me how to work the problem? \n" );
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Algebra.Com's Answer #121835 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! area of rectangle: \n" ); document.write( "width*height \n" ); document.write( "25*20 = 500 square feet \n" ); document.write( ". \n" ); document.write( "area of half circle: \n" ); document.write( "area for a full circle = (pi)r^2 \n" ); document.write( "half circle would be half of the above: \n" ); document.write( "(1/2)(pi)r^2 \n" ); document.write( "plugging in our values: \n" ); document.write( "(1/2)(3.14)10^2 \n" ); document.write( "(1/2)(3.14)100 \n" ); document.write( "(3.14)50 \n" ); document.write( "157 square feet \n" ); document.write( ". \n" ); document.write( "Area of shaded region is: \n" ); document.write( "\"area of rectangle\" - \"area of half circle\" \n" ); document.write( "500 - 157 = 343 square feet \n" ); document.write( ". \n" ); document.write( "Perimeter: \n" ); document.write( "Edge along the rectangle: \n" ); document.write( "height + 2(width) \n" ); document.write( "20 + 2(25) \n" ); document.write( "20 + 50 \n" ); document.write( "70 feet \n" ); document.write( ". \n" ); document.write( "Edge along the half-circle: \n" ); document.write( "\"circumference of a full circle\" is \n" ); document.write( "(pi)(d) \n" ); document.write( "we only want half of that so: \n" ); document.write( "(1/2)(pi)(d) \n" ); document.write( "(1/2)(3.14)(20) \n" ); document.write( "(3.14)(10) \n" ); document.write( "31.4 feet \n" ); document.write( ". \n" ); document.write( "Perimeter then is: \n" ); document.write( "70 + 31.4 = 101.4 feet \n" ); document.write( " |