document.write( "Question 165278This question is from textbook
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\n" ); document.write( "2^3x+1=13.4\r
\n" ); document.write( "\n" ); document.write( "Please let me know if I am wrong, Thanks\r
\n" ); document.write( "\n" ); document.write( "log2^3x+1 = log13.4
\n" ); document.write( "(3x+1)log2 = log13.4
\n" ); document.write( "3x+1 = log13.4/log2
\n" ); document.write( "3x+1-1 = 3.7441-1
\n" ); document.write( "3x = 2.7441
\n" ); document.write( "3x/3 = 2.7441/3
\n" ); document.write( "x=.9147 \n" ); document.write( "

Algebra.Com's Answer #121833 by padmameesala(42) $\"\"$ $\"About$

You can put this solution on YOUR website!
You are aboslutely done well, your answer is right
\n" ); document.write( "keep it up
\n" ); document.write( "Good luck.
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